1.1
1.
Cross-Curricular Writing Rubrics; High School Honors Portfolio; English Language Arts. 6th Grade ELA- Unit Plans & Resources. Unit 1 Resources. Child will encounter in its math development. When a child can multiply (and divide) without much thinking and without falling back on adding numbers, it will learn all future math topics much easier. Its all related! Children who can not, or have difficulties in reciting the times tables will lack speed and accuracy to master more.
Soln:
A man can enter the stadium in 4 ways. Again the man can leave the stadium in 9 ways.
So, total no.of ways with which a man enters and then leaves the stadium = 4 * 9 = 36ways.
2.
Soln:
There are 6 choices for a student to enter the hostel. There are 5 choices for a student to leave the hostel as different door is to be used.
So, total no.of ways = 6 * 5 = 30.
3.
Soln:
There are 7 choices for 1st son, 6 choices for 2nd son and 5 choices for 3rd son.
Now, by the basic principle of counting, the total number of ways of choice = 7 * 6 * 5 = 210.
4.
Unit4 Agendasmrs. Colville's Math Classes
Soln:
A man can go from city A to city B in 5 ways. As he has to return by a different road, so he can return from city B to city A in 4 ways.
So, total no.of ways by which a man can go from city A to city B and returns by a different road = 5 * 4 = 20 ways.
5.
Soln:
Unit4 Agendasmrs. Colville's Math Classroom
A person can go from city A to city B in 5 ways. Again, he can go from city B to city C in 4 ways. So, a person can go from city A to city C in 5 * 4 = 20ways. The person has to return from C to A without driving on the same road twice, So, he can return from city C to city B in 3 ways and from city B to city A in 4 ways.
So, he can return from city C to city A in 3 * 4 = 12 ways.
Download steam for mac os x 10.5.8. So, Total no.of ways by which a person can go from city A to city C and return from city C to city A = 20 * 12 = 240 ways.
6.
Soln:
Numbers formed should be of at least 3 digits means they may be of 3 digits, 4 digits, 5 digits or 6 digits.
How to fix the library search index on papers 3 for mac. There are 6 choices for digit in the units place. There are 5 and 4 choices for digits in ten and hundred’s place respectively.
So, total number of ways by which 3 digits numbers can be formed = 6.5.4 = 120
Similarly, the total no.of ways by which 4 digits numbers can be formed = 6.5.4.3 = 360.
the total no. of ways by which 5 digits numbers can be formed = 6.5.4.3.2 = 720.
The total no.of ways by which 4 digits numbers can be formed = 6.5.4.3.2.1 = 720.
So, total no.of ways by which the numbers of at least 3 digits can be formed = 120 + 360 + 720 + 720 = 1920.
7.
Soln:
The numbers formed must be of three digits and less than 500, so the digit in the hundred’s place should be 1,2,3 or 4. So, there are 4 choices for the digit in the hundred’s place. There are 5 choice for the digit in the ten’s place. There are 4 choices for the digit in the unit’s place.
Unit4 Agendasmrs. Colville's Math Class 9
So, no of ways by which 3 digits numbers les than 500 can be formed = 4.5.4 = 80. Aaron brooks.
8.
Soln:
The numbers formed should be even. So, the digit in the unit’s place must be 2 or 4. So, the digit in unit’s place must be 2 or 4. So, for the digit in unit’s place, there are 2 choices. So, after fixing the digit in the unit’s place, remaining 4 figures can be arranged in P(4,4) ways.
Ie. $frac{{left( 4 right)!}}{{left( {4 - 4} right)!}}$ = $frac{{4!}}{{0!}}$ = $frac{{4{rm{*}}3{rm{*}}2{rm{*}}1}}{1}$ = 24 ways.
Unit4 Agendasmrs. Colville's Math Class 6
So, total no.of ways by which 5 even numbers can be formed = 2 * 24 = 48.
9.
Soln:
The numbers formed must be of 4 digits. The digit in the thousand’s place must always be 4. For this, there is only one choice. After that, n = 6 – 1 = 5, r = 4 – 1 = 3. Then remaining 5 figures can be placed in remaining 3 places in:
Or, P(5,3) ways = $frac{{5!}}{{left( {5 - 3} right)!}}$ = $frac{{5!}}{{2!}}$ = $frac{{5{rm{*}}4{rm{*}}3{rm{*}}2{rm{*}}1}}{{2{rm{*}}1}}$ = 60 ways.
So, Total no.of ways by which 4 digits numbers between 4,000 and 5,000 can be formed = 1 * 60 = 60.
10.
Soln:
For the three digits numbers, there are 5 ways to fill in the 1st place, there are 4 ways to fill in the 2nd place and there are 3 ways to fill in the 3rd place. By the basic principle of counting, number of three digits numbers = 5 * 4 * 3 = 60.
Again, for three digit numbers which are divisible by 5, the number in the unit place must be 5. So, the unit place can be filled up in 1 way. After filling up the unit place 4 numbers are left. Ten’s place can be filled up in 4 ways and hundredths place can be filled up in 3 ways. Then by the basic principle of counting, no.of 3 digits numbers which are divisible by 5 = 1 * 4 * 3 = 12.
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MENSAJE IMPORTANTE: 1/19/2021, 10:40 AM -- Refresque la página para actualizar mensaje
MCPS prestará servicios limitados de apoyo técnico en persona y apoyo para devolución en 45 W. Gude Drive, el jueves 21 y viernes 22 de enero.Las familias y el personal que necesiten ayuda para Chromebooks podrán recibirla a través de un servicio de autobús móvil en el lugar. El apoyo técnico por teléfono continuará como siempre, llamando al 240-740-7020. El personal dirigirá a los visitantes a medida que vayan llegando, ya que se deberá respetar las importantes medidas de distanciamiento físico y el uso de máscaras de protección.